[Rabbit]

There are only three swimmers in the 100m freestyle. Swimmer A is twice as likely to win as B and three times as likely to win as C. Find the probablity that B or C wins

[Rampage]

There are only three swimmers in the 100m freestyle. Swimmer A is twice as likely to win as B and three times as likely to win as C. Find the probablity that B or C wins

this becomes an easy double equation. a=2b as well as a=3c
you can also model it out. give Swimmer A three parts, Swimmer B two parts, and Swimmer C one part. This makes Swimmer A three times more likely to win than swimmer C, and twice as likely to win as Swimmer B. The question asks what is the probability that B or C wins. Following the model, there is a 50% chance that either Swimmer B or Swimmer C will win.

[Rabbit]

if you because a=2b. if B has 2 parts then A has to have 4 parts

[SmG Dragonrage]

A + b + c = 100
A + 1/2a + 1/3a = 100
11/6a = 100
11a = 600
A = 600/11
2b=600/11
3c=600/11
B+c = 300/11 + 200/11
Simplify and u get ur answer

[Omega]

I think thats wrong dragon..

[Rabbit]

ok i think i got le answer. its 3/11 for A , 2/11 for B and 6/11 for C. add it and its 5/11

[SmG Pulse]

Is that the answer?
Cuz chances of A are twice of B and thrice of C acc. to teh question, but the answer doesn't seem to satisfy the condition IMO

[SmG Dragonrage]

I think thats wrong dragon..

No it's right I was just using %'s. in fraction form it would be 6/11 for a 3/11 for b and 2/11 for c

[Omega]

ah alright because im like how can it be over 1 o_O