SmG Rabbit Wrote:A spinner is spun 3 times . The chances of getting Red is 3/5 and the chances of getting blue 2/5 .
1. The probability of getting 3 red is? is it (3/5)^3
2. two red?
3. at least 1 red?
PHOENIX HELP!
Whatever I haven't seen rabbit on xfire lately so ill post here.
1. This is the easy one. The probability of getting three reds in three spins is simply (3/5)*(3/5)*(3/5) or (3/5)^3.
2. This one is slightly harder. At first glance u would think it would be (3/5)*(3/5)*(2/5) but there are three different ways to get exactly two red in three spins. You could have red red blue, red blue red, or blue red red. Each of these much be calculated into the probability so u must multiply it by three so u get (3/5)*(3/5)*(2/5)*3
3. This one is the hardest Notice that it says at least one red. That means one red, two reds, or three reds would work since any of the would give u at least one red. Now there are several ways to calculate this but the easiest and most logical way is this way. There are three different ways to get exactly one red (e.g. Red blue blue, blue red blue, blue blue red) thre fore u must add each of these probabilities together this is equivilant to finding the probability of one of the ways and multiplying it by three-> (2/5)*(2/5)*(3/5) +(2/5)*(3/5)*(2/5) +(3/5)*(2/5)*(2/5)=3*(2/5)^2*(3/5). And since we already know the probability of getting exactly two and exactly three reds we can add them to the probability of getting exactly one red to get ur probabity of getting at least one red-> (3/5)^3 +(2/5)*(3/5)^2 +(2/5)^2*(3/5).
If any of this is unclear let me know.
![[Image: mla7mw8hs3u0g9czg.jpg?size_id=5]](http://www.mediafire.com/convkey/40fb/mla7mw8hs3u0g9czg.jpg?size_id=5)
